What is the equation of the line with slope -2 that passes through the point (4, 3)?

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Multiple Choice

What is the equation of the line with slope -2 that passes through the point (4, 3)?

Explanation:
Use the slope-intercept form y = mx + b. With slope m = -2 and the line passing through (4, 3), plug into y = mx + b: 3 = (-2)(4) + b, so 3 = -8 + b, giving b = 11. Therefore the equation is y = -2x + 11. You can verify by substituting x = 4: y = -2(4) + 11 = -8 + 11 = 3, which matches the point. If you try other intercepts like 3, 7, or -11, plugging x = 4 would yield values other than 3, so they don’t fit.

Use the slope-intercept form y = mx + b. With slope m = -2 and the line passing through (4, 3), plug into y = mx + b: 3 = (-2)(4) + b, so 3 = -8 + b, giving b = 11. Therefore the equation is y = -2x + 11. You can verify by substituting x = 4: y = -2(4) + 11 = -8 + 11 = 3, which matches the point. If you try other intercepts like 3, 7, or -11, plugging x = 4 would yield values other than 3, so they don’t fit.

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